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Print Ed Calculator Periodic Table Question 26 of 32 a Sapling Learning The aver

ID: 552770 • Letter: P

Question

Print Ed Calculator Periodic Table Question 26 of 32 a Sapling Learning The average kinetic energy of the molecules in a gas sample depends only on the temperature, T But given the same kinetic energies, a lighter molecule will move faster thán a heavier molecule. 3RT rms speed where R-8.314 J/(mol K) and. is molar mass in kilograms per mole. Note that a joule is the same as a kg m2/s What is the rms speed of O2 molecules at 389 K? Number m/s What is the rms speed of He atoms at 389 K? Number m/ s

Explanation / Answer

1)

Molar mass of O2,

mm = 32.0g/mol

= 0.032 Kg/mol

T = 389 K

vrms = sqrt (3*R*T/M)

here : T is temperature in Kelvin

and M is molar mass in Kg/mol

So,

vrms = sqrt(3*8.314*389.0/0.032)

= 551 m/s

Answer: 551 m/s

2)

Molar mass of He,

mm = 4.003g/mol

= 0.004003 Kg/mol

T = 389 K

vrms = sqrt (3*R*T/M)

here : T is temperature in Kelvin

and M is molar mass in Kg/mol

So,

vrms = sqrt(3*8.314*389.0/0.004003)

= 1557 m/s

Answer: 1557 m/s

Feel free to comment below if you have any doubts or if this answer do not work

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