Where are they getting 14 from? he most common base NaO and KOH. Oher strong bas

Question

Where are they getting 14 from?

he most common base NaO and KOH. Oher strong bases include h metals, such as Ca(OH)2. SrO)2. and Ba -T s are the hydroxide compounds of the alkali metals, such as nclude hydroxide compounds of the heavier alkaline earth Example 17: Fill in the missing information in the table below. Pay attention to the concentration of hydroxide in the last row of the table. [OH1 is NOT equal to 0.005M in 0.005M Ca(OHI Solution 0.25 M NaOH OH 0.25 M DOK 0.0050 M KOH 0.0050 M 2.36 0.0050 M Ca(OH)2 0.010 MM

Explanation / Answer

note that water will hdyrolys eitself as

H2O + H2O <-> H3O + OH-

Kequilibirum value for this is 10^-14

recall that

pKw = -log(Kw) = -log(10^-14) = 14

then

10^-14 = [H3O+][OH-]

-log(X) of all the equaiton

-log(10^-14) = -log([H3O+]) + -log([OH-]))

then

14 = pH + pOH is always true at 25°C

Therefore

pH = 14-pOH

if pOH is given/calcualted, then we can get pH

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