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owLv2 | Online teaching Is Owlv2 | Online Teachi X C cvg.cengagenow.com/ilrn/takeAssignment/takeCovalent Activity do?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; : Apps : kober portal D 2004 Saturn L300 H: web chemucsbedu -Baltimore Classificat Acute Viral Hepatitis Hepatitis A Treatme Jaundice: MedlinePl Other bookmarks Time Remaining: 1:45:19 UNIT TEST Use the References to access important values if needed for this question. Question 10 Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Question 17 Question 18 Question 19 Question 20 Question 21 Question 22 Question 23 Question 24 Question 25 Progress: 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2HBrgH2(g) Br2(l) ANSWER: kJ Submit Answer Try Another Version 1 item attempt remaining Not Visited 0/25 items Due Nov 2 at Previous Next 11:00 PM 8:38 PM 11/2/2017

Explanation / Answer

we have:

Hof(HBr(g)) = -36.4 KJ/mol

Hof(H2(g)) = 0.0 KJ/mol

Hof(Br2(l)) = 0.0 KJ/mol

we have the Balanced chemical equation as:

2 HBr(g) ---> H2(g) + Br2(l)

deltaHo rxn = 1*Hof(H2(g)) + 1*Hof(Br2(l)) - 2*Hof( HBr(g))

deltaHo rxn = 1*Hof(H2(g)) + 1*Hof(Br2(l)) - 2*Hof( HBr(g))

deltaHo rxn = 1*(0.0) + 1*(0.0) - 2*(-36.4)

deltaHo rxn = 72.8 KJ/mol

Answer:  72.8 KJ/mol

Feel free to comment below if you have any doubts or if this answer do not work

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