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is owLv2 | Online teaching × e chegg Study I Guided s x C cvg.cengagenow.com/ilrn/takeAssignment/takeCovalent Activity do?locator-assignment-take&takeAssignmentSessionLocator-assignment-take; : Apps : kober portal D 2004 Saturn L300 H: web chemucsbedu -Baltimore Classificat Acute Viral Hepatitis Hepatitis A Treatme Jaundice: MedlinePl Other bookmarks Time Remaining; 1:39:26 UNIT TEST Use the References to access important values if needed for this question. Question 10 Question 11 Question 12 Question 13 Question 14 Question 15 Question 16 Question 17 Question 18 Question 19 Question 20 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt 1 pt 1 pr 1 pt 1 pt 1 pt The following thermochemical equation is for the reaction of carbon dioxide(g) with hydrogen(g) to form acetylene(g) (C2H2) and water(g) 2CO2(g)-5H2(g)-C-H2(g)-4H20(g) AH = 46.5 kJ When 12.3 grams of carbon dioxide(g) react with excess hydrogen(g) kJ of energy are Hint: An amount of energy is expressed as a positive mumber. The sign indicates whether the energy is absorbed or evolved. Submit Answer Try Another Version 1 item attempt remaining Question 22 Question 23 Question 24 Question 25 Progress: 0/25 items Due Nov 2 at Previous Next 11:00 PM 8:44 PM 11/2/2017Explanation / Answer
Molar mass of CO2 = 1*MM(C) + 2*MM(O)
= 1*12.01 + 2*16.0
= 44.01 g/mol
mass of CO2 = 12.3 g
we have below equation to be used:
number of mol of CO2,
n = mass of CO2/molar mass of CO2
=(12.3 g)/(44.01 g/mol)
= 0.2795 mol
Since delta H is positive, heat is absorbed
from reaction,
when 2 mol of CO2 reacts, heat absorbed = 46.5 KJ
so,
for 0.2795 mol, heat absorbed = 46.5*0.2795/2
= 6.50 KJ
Answer: 6.50 KJ, absorbed
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