Most of the sodium chlorate, NaCIO3, produced in the United States is converted

Question

Most of the sodium chlorate, NaCIO3, produced in the United States is converted into chlorine dioxide, which is then used for bleaching wood pulp. NaCIO3(aq) + 2 HCI(aq) CIO2(9) + ½ Cl2(9) + NaCl(aq) + H20( (a) How many milliliters of 11.5 M HCI are necessary to react completely with 38.67 g of sodium chlorate, NaCiO3? mL (b) What is the maximum mass, in grams, of CIO2 that can be formed from the complete reaction of 50. mL of 11.5 M HCI? 9 Supporting Materials Fundamental Constants Periodic Table Additional Materials Reading Listening

Explanation / Answer

NaClO3(aq) + 2HCl(aq) --------> ClO2(g) + 1/2Cl2(g) + NaCl(aq) + H2O(l)
no of moles of NaClO3 = W/G.M.Wt
                         = 38.67/106.5 = 0.36 moles
1 moles of NaClO3 react with 2 moles of HCl
0.36 moles of NaClO3 react with= 2*0.36/1 = 0.72 moles of HCl
no of moles = molarity * volume in L
0.72       = 11.5*volume in L
volume in L = 0.72/11.5 = 0.063L = 63ml>>>>answer
b.
no of moles of HCl = molarity * volume in L
                      = 11.5*0.05 = 0.575 moles
2 moles of HCl react with NaClO3 to gives 1 mole of ClO2
0.575 moles of HCl react with NaClO3 to gives = 0.575*1/2 = 0.2875 moles of ClO2
mass of ClO2 = no of moles * gram molar mass
              = 0.2875*83.5 = 24g of ClO2

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