Show your work. Do your own work. Type your answers. In equatorial African popul
ID: 55345 • Letter: S
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Show your work. Do your own work. Type your answers. In equatorial African populations, the frequency of the ticklc cell allele is 20%. In African American populations, the frequency of the sickle cell allele is 5%. In Caucasian American populations, the frequency of the sickle cell allele is 0.1%. What it the probability of any individual in these three populations being a heterozygote (earner of the disease)? What a the probability of any individual in these three populations being homozygous dominant? What is the probability of any individual in these three populations being homozygous recessive?Explanation / Answer
In equatorial african populations: The frequency of sickle cell allele is 20%
q= 0.2, then p +q=1, p= 1-0.2 = 0.8, 2pq = 2x0.8x0.2 = 0.32, q2 = 0.04, p2 = 0.64
In African american polulations:The frequency of sickle cell allele is 5%
q= 0.05, then p +q=1, p= 1- 0.05 = 0.95, 2pq = 2 x 0.95x 0.05 = 0.095, q2 = 0.0025, p2 = 0.9025
In cascarian american populations:The frequency of sickle cell allele is 0.1%
q= 0.001, then p +q=1, p= 1- 0.001 = 0.999, 2pq = 2 x 0.999x 0.001 = 0.001998, q2 = 0.000001, p2 = 0.998001
1. What is the probability of any individual in these three populations being a heterozygote (carrier of the disease)=
0.32 ,0.095 , 0.001998 (32%, 9.5%,0.1998% are heterozygous carriers in different populations in order)
2. What is the probability of any individual in these three populations being a homozygous dominant=
0.64,0.9025,0.998001(64%,90.25%,99.8% are homozygous dominant in different populations in order)
3. What is the probability of any individual in these three populations being a homozygous recessive=
0.04,0.0025,0.000001 (4%, 0.25%,0.0001% are homozygous recessive for the disease in different populations in order)
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