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Question 15 (of 15) value: 10.00 points 5 attempts left Check my work Be sure to

ID: 553565 • Letter: Q

Question

Question 15 (of 15) value: 10.00 points 5 attempts left Check my work Be sure to answer all parts. Chlorine oxide (CIO), which plays an important role in the depletion of ozone, decays rapidly according to the equation CIO(g) Cl2(g) + O2(g) From the following data, determine the reaction order and calculate the rate constant of the reaction. Time (s ICIOI (M 2.27 x 103 7.88 106 3.12 × 10-3 16.81 × 10-6 3.97 x 10-3 | 5.99 × 10-6 4.82 x 10-3 | 5.35 × 10-6 5.67 x 103 4.83 x 106 Reaction order: -10 Rate constant: k = Ms (Enter your answer in scientific notation.)

Explanation / Answer

the rate of ClO decomposition is related to order (n) and rate constant (K) is

-d[ClO]/dt= K [ClO]n, in the present case , integral method of analysis will be used, where the order will be used and the integrated expression wll be used to veriy the data

at t= 0, [ClO]= [ClO]o and t=t [ClO] = [ClO]

for zero order n=0 , -d[ClO]/dt= K , when integrated noting that t=0 [CLO] = [ClO]0 and t= t [ClO]= [ClO]

[ClO] =[ClO]o- Kt

hecne zero order has to be obeyed , a plot of [ClO] vs time has to be straight line.

for 1st order, n=1, -d[ClO]/dt= K[ClO], when integratedt=0 [CLO] = [ClO]0 and t= t [ClO]= [ClO] , ln[ClO] =ln[ClO]o-Kt ,so for 1st order reaction has to be obeyed, ln [ClO] vs time has to be straight line

for second order, n=2 -d[ClO]/dt= K[ClO]2, when intergated t=0 [CLO] = [ClO]0 and t= t [ClO]= [ClO]

1/[ClO] = 1/[ClO]o+ Kt, so a plot of 1/[ClO] vs t has to be straight line for 2nd order reaction to be obeyed.

All the three equations written above for zero order, 1st order and second order are verified by drawnig three different plots. They are shown below.

zero order reaction plot

1st order plot

2nd order plot is shown below

looking at the three plots, R2 value is 1 is highest for second order reaction. hence the reaction is second order.

hence the reaction is second order.

from the plot, K= slope = 2*107/M.s

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