Which is the correct molecular geometry (shape) of the following, respectively:

Question

Which is the correct molecular geometry (shape) of the following, respectively: ICl4^-1 ; BrF5 ; XeCl2F2 ; IOCl5 ; IF3
Answer choices: A) square planar, square planar, square pyramidal, octahedral, T-shaped B) square pyramidal, square planar, square planar, T-shaped, octahedral C) square pyramidal, square planar, square planar, octahedral, T-shaped D) T-shaped, octahedral, seesaw, square planar, square pyramidal E) Square planar, square pyramidal, square planar, octahedral, T-shaped Which is the correct molecular geometry (shape) of the following, respectively: ICl4^-1 ; BrF5 ; XeCl2F2 ; IOCl5 ; IF3
Answer choices: A) square planar, square planar, square pyramidal, octahedral, T-shaped B) square pyramidal, square planar, square planar, T-shaped, octahedral C) square pyramidal, square planar, square planar, octahedral, T-shaped D) T-shaped, octahedral, seesaw, square planar, square pyramidal E) Square planar, square pyramidal, square planar, octahedral, T-shaped ICl4^-1 ; BrF5 ; XeCl2F2 ; IOCl5 ; IF3
Answer choices: A) square planar, square planar, square pyramidal, octahedral, T-shaped B) square pyramidal, square planar, square planar, T-shaped, octahedral C) square pyramidal, square planar, square planar, octahedral, T-shaped D) T-shaped, octahedral, seesaw, square planar, square pyramidal E) Square planar, square pyramidal, square planar, octahedral, T-shaped

Explanation / Answer

Ans : E

ICl4- (four sigma bonds + two lone pairs = 6 = square planar.

BrF5 (five sigma bonds + one lone pair = 5 = Square pyramidal.

XeCl2F2 (four sigma bonds + two lone pairs = 6= square planar.

IOCl5 ( (6 sigma bonds = octahedral).

IF3 (3 sigma bonds + two lone pairs) = T-shaped.

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.