need help with question 1-3? 1. A pure porphyrin sample was analyzed and found t

Question

need help with question 1-3?

1. A pure porphyrin sample was analyzed and found to consist of 78 67% C, 4.95% H, 7 65% 0, and 73% Determine the empirical formula of the porphyrin al if the actual molecular mass of the porphyrin is 732.808g/mol, what is the molecular formula of this porphhyrin? b) 2. Calculate the solubility of CrH)ds) (Ksp·10 K 10"") in water. 3. One of the most common complexometric gravimetric procedures involves the use of a bidentate chelating agent such as dimethy'g/yoxime to determine Ni". Draw the structure of the Ni"complex of this ligand and name it

Explanation / Answer

Ans 1 :

a) Let the mass of porphyrin sample be 100 g

So the amount of C=78.67 g

Number of moles = 78.67 / 12.01 = 6.55 moles

H= 4.95 g

Moles = 4.95/1.008 = 4.91 moles

N= 7.65

Moles = 0.55

O= 8.73 g

Moles = 0.55 moles

dividing by a common factor , to get the ratio as : 11:9:1:1

So the empirical formula becomes : C12H9NO

b) Empirical mass = (12.01 x 12) + (1.008 x 9) + 14 + 16

= 183.192 g/mol

Dividing molecular mass by empirical mass we get :

= 732.808 / 183.192

= 4

Multiplying the empirical formula by 4 to get the molecular formula as :

= C48H36N4O4

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.