complete the following table for the aqueous solution of potassium complete the
ID: 554787 • Letter: C
Question
complete the following table for the aqueous solution of potassium complete the following table for the aqueous solution of potassium complete the following table for the aqueous solution of potassium Exam 3 Review I. Complete the following table for the aqueous solutions of potassium hydroxide. Density (g/mL) Mass Percent Mole Fraction of Solute Molarity Molality of Solute 1.13 1.29E AL 30.0 1.43 sample of a solution of TT 2. Lysozyme is an enzyme that cleaves cell walls. A 0.100 L lysozyme that contains 0.0750 g of the enzyme exhibits an osmotic pressure of 1.32 X 10-3 atm at 25°C. What is the molecular weight of lysozymeExplanation / Answer
1. Complete the following table.
a) Density = 1.05 g/ml
Molarity = 1.13 = moles of solute/volume of solution on liter
Volume of solution = 1 liter
mass of solution = 1050 g
moles of solute = 1.13
mass of solute = 1.13 x 56.1 = 63.39
mass of solvent = 1050 g - 63.39 g = 986.61 g
Molality = 1.13 / 0.987 = 1.14
mass percent of solute = (63.39 /1050 ) x 100 = 6.04 %
moles of solvent = 986.61/18 = 54.81
moles fraction of solute = 1.13 /(1.13 + 54.81) = 0.0202
b) Density = 1.29
Volume of solution = 1290 g
mass percentage of solute = 30.0
mass of solute = 0.30 x 1290 = 387.00 g
moles of solute = 387 /56.1 = 6.9
Molarity = 6.9
mass of solvent = 1290 - 387 = 903.0 g
molallity = 6.9 / 0.903 = 7.64
moles of solvent = 903 / 18 = 50.17
mole fraction of solute = 6.9 / 57.07 = 0.12
c) density = 1.43
Molality = 14.2
lets take the mass of solvent = 1000 g
moles of solute = 14.2
mass of solute = 796.62 g
mass of the solution = 1796.62 g
mass percent of solute = (796.62/1796.62) x 100= 44.34 %
volume of solution = 1796.62 / 1.43 = 1256.38 ml = 1.26 L
molality = 14.2 / 1.26 = 11.27
moles of solute = 55.56
mle fraction of solute = 14.2 / 69.76 = 0.203
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