ces Normal No Spacing Head (Cu(H2O)6)2+ (aq) + 2 OH\' Cu(OH), (s) + 6 Hao (1) 30

Question

ces Normal No Spacing Head (Cu(H2O)6)2+ (aq) + 2 OH' Cu(OH), (s) + 6 Hao (1) 30mL of 3.0 NaOH was added to the solution. The solution became teal and there was a clear layer on the top as the teal solution settled. This was expected. This solution was heated on a hot plate. The longer the solution was heated, the darker the solution became. The solid began to settle and there was a clear top layer Cu(OH)2 (s) CMQ (s) + H2O (1) The supernatant liquid was decanted twice. A red litmus test was done. The paper turney blue, proving the decanted liquid was basic. 15mL of 6.0M H2SO, was added to the separated product, the solution turned crystal blue. This was expected CuO(s) + 2 HO" (m) + 3 H2O (l) (CuOLO)-)" (aa) 3.0 g of zinc was massed out and slowly added to the blue solution and stirred. The blue began to fade and zine turned red and clumped in the middle. Eventually, the blue disappeared and all that was left was a clear solution and the zinc that had turned into red conper is was expected nglish (US)

Explanation / Answer

the difference is that the h2o in the product should be in gaseous state not in liquid state

it is write Cu(OH)2(s)(heat) = CuO(s) + H2O(g)

Reaction type: decomposition

for 2nd reaction ,it is also same error of state of product

CuO +( 2H3O)+ + 3H2O =( Cu(H2O)6) 2+

Compound Coefficient Molar Mass Moles Weight Cu(OH)2(s)(heat) 1 97.56068 CuO(s) 1 79.5454 H2O(g) 1 18.0152

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