at a winery glucose ( c6h12o6) in grapes undergoes fermentation to produce ethan

Question

at a winery glucose ( c6h12o6) in grapes undergoes fermentation to produce ethanol ( c2h6o) and carbon dioxide. c6h12o6- 2c2h6o+ 2co2. (a) how many grams of glucose are required to form

124g of ethanol?

our next eran t a l una prepare for lucose (CH120) in grapes undergoes en tation to produce (6, 7) 151 Glucose Ethanol Glucose in grapes ferments to produce ethanol. a. How many grams of glucose are required to form 124 g of ethanol? reaction of 0.240 kg of glucose? enote give garhon dioxide and water. (1,6,7) h. How many grams of ethanol would be formed from the 148 Gasohol is a

Explanation / Answer

From the balanced equation for fermentation of glucose, from law of mass conservation it can be seen that for every mole of glucose two moles of ethanol and carbon dioxide are formed. So, if the no.of moles of ethanol in 124g of it is found, we can say that half that no.of moles of glucose will be formed. Then, knowing the molar mass of glucose, we can find the quantity of glucose in that many moles of it, in grams. Similar procedure followed from no.of moles of glucose in the quantity given in part B will give the quantity of ethanol produced in grams.

The molar mass of ethanol is 46g/mol and that of glucose is 180g/mol.

a) No.of moles of ethanol in 124g = 124/46 = 2.6956moles. This would have risen from 2.6956/2 = 1.3478moles of glucose. This comes to 1.3478x180 = 242.604. So, 242.604g of glucose is required to produce 124g of ethanol.

b) 240g of glucose contains 240/180 = 1.3333moles. This will give rise to 1.3333x2 = 2.6666moles of ethanol. In grams, this will turn out to be 2.6666moles x 46g/mol = 122.6636g of ethanol. So, 0.24kg of glucose will produce 122.6636g of ethanol.

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