1) A 0.0641 M solution was prepared by dissolving copper wire (AW = 63.546) in n
ID: 555876 • Letter: 1
Question
1) A 0.0641 M solution was prepared by dissolving copper wire (AW = 63.546) in nitric acid and diluting to volume in a 100mL volumetric flask with distilled water. What was the mass of the copper wire?
2)A standard solution has an absorbance of .237. An unknown solution has an absorbance of .141. Is the concentration of the unknown higher, lower, or the same as the concentration of the standard? Multiple choce . Pick One answer
A) Higher B) Lower C) SAME
3) Given the following values were obtained from a UV/Vis instrument set to 625nm, what is the absorbance of the solution?
Blank 98.3%; Standard 39.1%
Explanation / Answer
A)
M = mol/V
V = 100 mL = 0.1 L
mol = M*V = (0.0641 *0.1) = 0.00641 of Copper
mass = mol*MW = 0.00641 *63.546 = 0.40732986 g of Copper present
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