When propane (C3Hs) burns, it reacts with oxygen gas to produce carbon dioxide a

Question

When propane (C3Hs) burns, it reacts with oxygen gas to produce carbon dioxide and water. The unbalanced equation for this reaction is C3H8 (g) + O2(g) CO2(g) + H2O(g) This type of reaction is referred to as a complete combustion reaction What coefficients are needed to balance the equation for the complete combustion of propane? Enter the coefficients in the order C3Hs. 02. CO2, and H20, respectively Express your answer as four integers, separated by commas (e.g., 1,2,3,4) 1, 3, 8,4 QUESTION 3 in the previous problem, what mass of oxygen is needed for the complete combustion of 5.30x 10 g of propane? Write your answer with the proper number of significant figures and without using scientific notation.

Explanation / Answer

The reaction is:

C3H8 + O2 —> CO2 + H2O

balance C:

C3H8 + O2 —> 3 CO2 + H2O

balance H:

C3H8 + O2 —> 3 CO2 + 4 H2O

balance O:

C3H8 + 5 O2 —> 3 CO2 + 4 H2O

Answer: 1, 5, 3, 4

3)

Molar mass of C3H8 = 3*MM(C) + 8*MM(H)

= 3*12.01 + 8*1.008

= 44.094 g/mol

mass of C3H8 = 0.0053 g

mol of C3H8 = (mass)/(molar mass)

= 5.30*10^-3/44.094

= 1.20*10^-4 mol

From balanced chemical reaction, we see that

when 1 mol of C3H8 reacts, 5 mol of O2 is Reacting

mol of O2 reacting = (5/1)* moles of C3H8

= (5/1)*1.20*10^-4

= 6.00*10^-4 mol

Molar mass of O2 = 32 g/mol

mass of O2 = number of mol * molar mass

= 6.00*10^-4*32

= 0.0192 g

Answer: = 0.0192 g

Feel free to comment below if you have any doubts or if this answer do not work

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