JolutiuT StUICtiometry ch, Second Edition 135. What volume of 0.0521 M Ba(OH), i

Question

JolutiuT StUICtiometry ch, Second Edition 135. What volume of 0.0521 M Ba(OH), is required to neutralize exactly 14.20 mlof 0.141 M H,Po? Phosphoric acid contains three acidic hydrogens. 136. A 10.00-ml sample of sulfuric acid from an automobile battery requires 35.08 mL of 2.12 sodium hydroxide solution for complete neutralization. What is the molarity of the sulfu acid? Sulfuric acid contains two acidic hydrogens. 137. A 0.500-L sample of H,SO, solution was analyzed by taking a 100.0-ml aliquot and adding 50.0 ml of 0.213 M NaOH. After the reaction occurred, an excess of OH ions remained in the solution. The excess base required 13.21 mL of 0.103 M HCI for neutralization. Calculate the molarlty of the original sample of HaSO. Sulfurie acld has two acidic hydrogens. Answer 138. A 6.50-g sample of a diprotic acld requires 137.5 ml of a 0.750 M NaOH solution for complete neutralization. Determine the molar mass of the acld. 139. Citric acid, which can be obtained from lemon juice, has the molecular formula Ca H Or. A 0.250-g sample of citric acid dissolved in 25.0 ml of water requires 37.2 mL of 0.105 M NaOH for complete neutralization. What number of acidie hydrogens per molecule does éitric acid have? 140. A stream flows at a tate of 5.00 x 10t ltters per second (L/s) upstre am of a manufacturing TOSHIBA 5 6 7 8 9 0 RTYUOP

Explanation / Answer

136. A. 10 ml *M = 35.08 ml * 2.12 M

or, M = 7.436 molar

137. moles of HCl = 0.103 mole / lit * 0.01321 lit = 0.00136 mole = the excess mole of NaOH

total moles of NaOH =0.213 mole /it * 0.050 lit = 0.01065 mole

mole in 100 ml H2SO4 = 0.01065 mole - 0.00136 mole = 0.00929 mole

total mole in 0.5 L = 0.00929 *0.5 mole

hence, molarity = 0.00929 *0.5 mole / 0.5 L =  0.00929 M

138. moles of NaoH = 0.1375 L * 0.750 mole /lit =0.103125 mole = mole of acid

hence, molar mass = 6.50 gm / 0.103125 mole = 63.03 gm /mole

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