m/ibiscms/mod/ibis/view.php?id 4220344 tion 4 of 6 Sapli ng Learning Saturated a
ID: 557379 • Letter: M
Question
m/ibiscms/mod/ibis/view.php?id 4220344 tion 4 of 6 Sapli ng Learning Saturated acetone vapor enters a heat exchanger at a rate of 2.30 Uis at 1 atm, and emerges from the heat exchanger as V,-2.30 Us acetone a saturated iquid at the same pressure. Water at 1 atm enters the heat exchangerP,-1 atm at 120 C and at a rate of 4.61 molis Assume that the heat exchanger operates adiabatically with respect to its sumoundings Calculate the tempersture of exiting water by folowing the steps below Ti ns 4.61 molis water 4 61 moes water temperature does acetone enter P-1 tm acetone enter the heat exchanger? T4 . 12.0 Number o C What is the heat of vaporization of acelone at this temperabore? kJ/ mol Use the ideal gas law to calculate the moles of acetone entering the heat exchanger Scroll down for more questions mol/s OPmcu. @chea Answ+0 Nexi 8E." HintExplanation / Answer
a) Since we are working with 1 atm we just need to get the boiling point of acetone which is 56 C
Initial temperature is 56 C or
273.15 + 56 = 329.15 K
B) Heat of vaporization according to internet at this temperature is 31.3 KJ / mol
C) ideal gas equation for moles
moles = Pressure * Volume / (R * Temperature)
assuming a basis of 1 sec
Pressure is 1 atm
Volume is 2.3 L
R is gas constant 0.082
Temperature is 329.15 K
moles = 1 * 2.3 / (0.082 * 329.15) = 0.08521 moles
d) you have to apply equation of heat exchange between a vapor that is condensing and the heat gained by liquid water
moles of vapor * heat of vaporization = moles of water * Heat capacity * (Tf - Ti)
0.08521 * 31.3KJ / mol = 4.61 mol * 0.0754 KJ / mol * (Tf - 12) , Ti comes from the statement
2.667 = 0.347594 * (Tf - 12)
2.667 / 0.347594 = Tf - 12
7.6727 = Tf - 12
Tf = 7.6727 + 12 = 19.67 C
*Please rate the answer if you like it =)
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.