Exercise For questions 1-2, use the equation: 1. Using the male ratia, determine

Question

Exercise For questions 1-2, use the equation: 1. Using the male ratia, determine the number of grans of hydrated salt, CdBr2 4H20, that would be required to yield 0.0457 moles of water? SHON HORK. 2. (a) Using the nole ratio. calculate the mass of water that could be driven from 2.536 grams of the hydrated salt, CdBra-4H20, assuming that the enhydrous salt is obtained. SHCW wo vng tnat the ange rou i l ir gbt ined.: saa wk (b) Ustng the experimental data fron pert (a), deternine the percent water in the 2.536 grans of hydrate. SHOW WORK A hydrated salt is 45.7% water by nass. (a) Calculate the nass of water in 1.578 g of MS04-7Hg0. SHON WORK. (b) Using (a) above and the ole ratie, calculate the moles of anhydrous salt, M504 1n g of N504-7H20. SHON WORK

Explanation / Answer

Q1

ratio is

1 mol of hydrated salt = 4 mol of water

then

mol of 0.0457 of water ... -->

0.0457 /4 = 0.011425 mol of hydrated salt

MW of hydrated salt = CdBr2 + 4H2O = 272.219+ 4*18 = 344.219 g/ mol

mass = mol*MW = 0.011425*344.219 = 3.93270 g of hyrated salt.

Q2.

a)

mass of water from

2.536 g of hydrated salt

344.219 g of hydrate = 4*18 = 72 g of water

then

2.536 g of hydrate -- > x

x = 2.536 /344.219 *72

x = 0.530 g of water can be recovered

b)

% of water in 2.536 g of hydrated

% water = mass of water / Total mass * 100% = 0.530 / 2.536 * 100 = 20.8990 % is water

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