Give the balanced equation for the solvation of Ca(OH)2 in water. Write the solu

Question

Give the balanced equation for the solvation of Ca(OH)2 in water. Write the solubility-product expression, Kup, for Ca(OH) Explain in complete sentences using equations if necessary for illustration. 1. What is the stoichiometric relationship of the hydroxide ion concentration to calcium ion concentration? 2 moits of on pce moies FoeMC R words for everq moie of Ca21 added, there will be In 0ihe 2. What is the stoichiometric relationship of the solubility of Ca(OH)2 to the concentration of OH in solution? 2 moles of ot1 forms from ca (ot)z dussolvtion. For evey one i move orca( on ) 2n moles of (on- wai bein 3. What is the stoichiometric relationship of the solubility of Ca(OH)2 to the concentration of 1 moie of ca+ forms when Calotya dissolves. Ca in solution? For every I mole of move or (Catortz,imoie of Car qoes 4. Using LeChatlier's Principle whateeor the addition oft the addition of the common ion, Ca2', on the solubility of Ca(OH)2? It will decrease the solubility of Calon, , shifting 5. What is the expected effect of the addition of the common ion on Kp? i o tme ceet. Tme vave of espus not rfccred by nt cumminim ettect 6. Write the balanced equation for the neutralization of calcium hydroxide by hydrochlorie 79

Explanation / Answer

a) since you got the same values in both trials for part 1 the average solubility will be 0.02384 M

average ksp will be 5.42x105

the solubility is 0.02384 M, units of M are mol / L so:

0.02384 mol / L , we need the molar mass of Ca(OH)2 which is 74 g/gmol, the first step is to get g / liter, we have to multiply the molarity by the molar mass

0.02384 mol / L * 74 g/gmol = 1.76416 g / L, you have 1.764 g in 1000 ml, you want to know the value in 100 ml, just divide it by 10, you will get 0.1764 g/ 100 ml

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