Part D When solving problems involving stoichiometric coefficients, the first st

Question

Part D When solving problems involving stoichiometric coefficients, the first step is to make sure you have a balanced chemical equation. Then, you determine the limiting reagent by using the coefficients from the balanced equation. You can keep track of the amounts of all reactant and products before and after a reaction using an ICF table. Completing the ICF table will also allow you to determine the limiting reagent, and the amount of product formed assumes that the reaction runs to com with 100% yield. Parts A and C explore these steps in more detail. Let us consider another reaction. Ammonia and oxygen react to form nitrogen monoxide and water. Construct your own balanced equation to determine the amount of NO and H20 that would form when 3.05 mol NH3 and 6.41 mol O2 react. Express the amounts in moles to two decimal places separated by a comma. You did not open hints for this part. ANSWER amount of NO, amount of H2O mol 5/5 View?view print&assignmentProblemID-92915436;

Explanation / Answer

balanced chemical equation :

4 NH3    + 5 O2 ------------------> 4 NO   + 6 H2O

4mol      5 mol                           4                   6

3.05 mol     6.41 mol

moles ratio of NH3 = 3.05 / 4 = 0.762

moles ratio of O2 = 6.41 / 5 = 1.28

moles ratio of NH3 is smaller than O2 . so NH3 is limiting reagent

so products based on limiting reagent

moles of NO formed = 3.05 x 4 / 4 = 3.05

moles of H2O = 6 x 3.05 / 4 = 4.58

amount of NO , amount of H2O = 3.05 , 4.58

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.