How would I find the molarity of NaOH based of this data? I dont know if you nee

Question

How would I find the molarity of NaOH based of this data? I dont know if you need to know that the molarity of KHP is .023319.

G Google G Molarity (M) of the NaO untitled Chem2 1 Labs x x www4.chem2 1 labs.com/student2/?mode-assign&assignment;:93 Standardization of NaOH Trial 2 Line 1 12 5.5570,12.133 10 4. Volume (mL) of KHP solution used for titration 19.75 19.6 Try 1: X 7.8370 Try 2: X 7.8590 Try 3: X 7.837 Correct 3.0 2. Volume (mL) of base at the Equivalence Point Try 1:2.97 You MUST click EACH graph link above before submitting this answer. 0.5 0.5 Enter the x value of the Cursor's position this is in the upper left corner of the graph!! 0 0.5 3. Molarity (M) of the NaOH solution NG 0.5 NG 0.5

Explanation / Answer

1 mole of KHP reacts with 1 mole of NaOH

Trial #1,

moles of KHP reacted = 0.023319 M x 19.6 ml = 0.46 mmol

moles NaOH added = 0.46 mmol

volume of NaOH to reach equivalence point = 3.0 ml

molarity of NaOH solution = 0.46 mmol/3 ml = 0.153 M

Trial #2,

moles of KHP reacted = 0.023319 M x 19.75 ml = 0.46 mmol

moles NaOH to reach equivalence point = 0.46 mmol

volume of NaOH to reach equivalence point = 3.0 ml

molarity of NaOH solution = 0.46 mmol/3 ml = 0.153 M

Average molarity of NaOH = 0.153 M

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