13. Complete the following chemical equation and balance it. (6 points) AgNO3 +

Question

13. Complete the following chemical equation and balance it. (6 points) AgNO3 + Na3PO4 14. Consider the following reaction: NaCl + AgNO3 NaNO3 + AgCl (6 points) A. This reaction does not proceed because one of the starting compounds is insoluble B. This reaction does not proceed because one of the starting compounds is soluble. C. This reaction proceeds because it forms a soluble product. D. This reaction proceeds because it forms an insoluble product. E. Since it is not a redox reaction, no predictions about the reaction can be made 15. BaSO4 + MgCl2 BaCl2+ MgSO4 (6 points) A. This reaction does not proceed because one of the starting compounds is insoluble. B. This reaction does not proceed because one of the starting compounds is soluble. C. This reaction proceeds because it forms a soluble product. D. This reaction proceeds because it forms an insoluble product. E. Since it is not a redox reaction, no predictions about the reaction can be made Extra credit. Balance the equation below by adding the appropriate numbers. Pb(NO3)2 + KI PbI2 + KNO3 If 1mL of 0.06 M of lead nitrate solution and 2 mL of 0.1 M of potassium iodide solution are reacted, how many grams of lead iodide are produced? Pbl2 molecular weight = 461 g/mole (10 points) A. 60 mg B. 27.7 mg C. 200 mg D. 47.7 mg E. 0.001 mg

Explanation / Answer

Q13

there will be precipitation of silver phosphate

so

3AgNO3(aq) + Na3PO4(aq) = Ag3PO4(s) + 6NaNO3(aq)

Q14

the reaction is likely to from Agcl as a produce (solid)

choose D

Q15

note likely to occur, since BaSO4 is solid

choose A

Qextra

Pb(NO3)2 + 2KI = PbI2 + 2KNO3

mol of lead = MV = 1*0.06 = 0.06

mol of I = MV = 2*0.1 = 0.2

ratio is 1:2 so there is excess lead

mol of PbI2 formed = 0.2/2 = 0.1

mass = mmol*MW = 0.1*461 = 46.1 mg

nearest answer is 47 mg

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