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or Excel Online Select PDF file 254 Eerste E..men 2015.pdf Convert to Microsoft

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Question

or Excel Online Select PDF file 254 Eerste E..men 2015.pdf Convert to Microsoft Word (*.docx) v er dit verhit nder Document Language: English (U.S.) Change KP, by 25 °C. -dui. ntalpie as Ammonium chloride decomposes when heated according to the reaction given below. (a) Calculate the equilibrium constant, Kp, at 25 °C for the equilibrium as given below. (b) Calculate Kp at 200 °C. Consider enthalpy as being independent of temperature. (c) At what temperature will Kp = 1? Convert a Create PDF A Edit PDF NH4Cl(s) = NH3(g) + HCl(g) O Comment Store and share files in the Document Cloud Learn More E O S Au D A W A (G. 1) 114217

Explanation / Answer

a)

Kp at 25°C

dG = Gproducts - Greactants

dG = NH3 + HCl - (NH4Cl)

dG = -16.4 + -95.3 - (-202.9 ) = 91.2 kJ/mol

dG = 91.2 J/mol

dG = -RT*ln(K)

K = exp(-DG/(RT))

K = exp(-91200 /(8.314*298))

K= 1.0316*10^-16

b)

calcualte at T = 200°C...

dH = NH3 + HCl - (NH4Cl)

dH = -80.29 + -92.3 - (-314.4) = 141.81 kJ/mol

dS = NH3 + HCl - (NH4Cl)

dS = 192.8 + 186.9 - 94.6 = 285.1

now

dG = dH - T*dS = 141.81 - (200+273)* 285.1/1000 = 6.9577 kJ/mol

dG = -RT*ln(K)

K = exp(-DG/(RT))

K = exp(-6957.7/(8.314*(200+273))

K = 0.17045

c)

if Kp = 1

dG = -RT*ln(Kp)

dG = 0

dH - T*dS = 0

141810 - T *  285.1 = 0

T = 141810 /285.1

T = 497 K