QUESTION 27 1. Which of the following is not a postulate of the Kinetic Molecula

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QUESTION 27 1. Which of the following is not a postulate of the Kinetic Molecular Theory as applied to the gaseous state? Molecules of a gas move rapidly and in straight lines until defected by collisions with other molecules or the sides of the container. The molecules in a gas are tiny compared to the distance between them The molecules of a gas are strongly attracted to each other If two molecules collide with each other, the total energy of the molecules before the collision is the same as their total energy after the collision. QUESTION 28 What is the mass of 14.0 moles of ammonia, NHs? 1. 14.0 grams 56.0 grams 239 grams 23.8 grams QUESTION 29 1. Wich of the folowing is the correct relationship between he number of grams of the element phos correct relationship between the n umber of grams of the element phosphorus and the number of atoms of the element phosphorus? C 15 grams of P contain 1 atom of P 15.00 grams of P contain 6.02 x 1021 atoms P 30.97 grams of P contain 1 atom of P 30.97 grams of P contain 6.02 x 1023 atoms P QUESTION 30 with distilled water? 0.17 M HC 1.5 M HCI 3.67 M HC 37.5 M HCI QUESTION 31 1. What is the molarity of the new solution if 25 mL of a 0.50 M HCI solution is diluted to a total volume of 75 ml. 1. Which of the following will increase the pressure of a confined sample of gas? Decreasing volume at constant temperature Temperature decreasing at constant volume Container increases in size at constant temperature Heating the sample of gas at a constant volume Both a&c; C Both a&d;

Explanation / Answer

1) the assumption is there is no force between molecules of gas so (c) is the answer because there is no attraction between molecules.

2) mass of ammonia= moles*mol.wt.= 14*17= 238 gm (c)

3) mol. Wt of P= 30.97

So 30.97 gm contains 6.02*10^23 atoms of P

4) molarity= moles of solute/volume of sol.

= 25*0.5/75= 0.167 M (a)

5) PV= nRT

So pressure can be increased by either reducing volume at constant temperature or by increasing temperature at constant volume. So both (a) and (d) are correct.

6) volume of sol.= Moles of solute/molarity

= (45/58.5)/5.3 = 4.081 L= 4081 ml

7) has a definite volume but no definite shape

8) molarity= (25/95)/0.5 = 0.525M

9) at constant Pressure V1/V2 = T1/T2

V2= V1T2/T1= 4*298/233 = 4.9 L

10) volume will increase

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