13. Which one of these salts will form a neutral solution on dissolving in water
ID: 560137 • Letter: 1
Question
13. Which one of these salts will form a neutral solution on dissolving in water? sirong actd 14. Which one of these salts will form a basic solution on dissolving in water? Neutral acidT 5. Phosphoric acid has three pKa values, pKa. I= 2.12, pKa, 2-68; and pKa, 13 = 12.5. which ne of these pKa values would be most useful to solve for the pH of a solution of 0.30 M H2PO4? ) pKa. B) pKa,2 C) pKa, 3 D) none of these would be useful ) impossible to answer without further information. 6. 1.25 moles of NOCI were placed in a 2.50 L reaction chamber at 427°C. After equilibrium was reached, 1.10 moles of NOCI remained. Calculate the equilibrium constant, Ke, for the reaction 2NOCI(g) 2NO(g) + Cl2(g). A) 3.0 × 10-4 B) 1.8 × 103 C) 1.4 x 10-3 D) 5.6 x 104 E) 4.1x 10-3Explanation / Answer
13) A) KCl
Reason : KCl is a salt of strong base KOH and strong acid HCl
14) D) NH4NO3
Reason: NH4NO3 is a salt of weak base NH3 and strong acid HNO3
15) B) pKa,2
16)
we know that
concentration = moles / volume (L)
so
initial conc of NOCl = 1.25 / 2.5 = 0.5 M
equilibrium conc of NOCl = 1.1 / 2.5 = 0.44 M
now
consider the reaction
2 NOCl <---> 2 NO + Cl2
using ICE table
initial conc of NOCl, NO,Cl2 are 0.5 , 0 , 0
change in conc of NOCl, NO,Cl2 are -2y , +2y , y
equilibrium conc of NOCl,NO,Cl2 are 0.5-2y , 2y , y
now
[NOCl]eq = 0.5 - 2y = 0.44
y = 0.03
so
[NOCl]eq = 0.44 M
[NO]eq = 2y = 2 x 0.03 = 0.06 M
[Cl2]eq = y = 0.03 M
now
Keq = [NO]^2 [Cl2] / [NOCl]^2
Keq = (0.06)^2 (0.03) / (0.44)^2
Keq = 5.58 x 10-4
so
the answer is option D ) 5.6 x 10-4
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