Determine how to make 500 grams of a mixture that is 8% powdered gypsum in sand?

Question

Determine how to make 500 grams of a mixture that is 8% powdered gypsum in sand? in this case since your mixing two solids the units of your expression on the right side of the equals signs will be in gram/gram.

Describe how to make a 50mL of a 10% solution of dextrose (table sugar) in water

If you mix together 5 grams of dextrose and 400 mLs of water, what percent solution would you have made?

Starting with a bottle of Tween, a liquid detergent with a FW of 1227.4 g/mol, describe how you would prepare 0.5 L of a 2 M solution in water.

Starting with a bottle of sodium phosphate, a common buffer used in growth media, which has a FW if 120 g/mol, describe how you would prepare 250 mL of a 0.5 mM solution in water.

If you were to add 60 grams of sodium phosphate to 0.25 L of water, what would the molarity be?

Describe how to make 200mL of a 0.3 M solution of Tris using a 1.0 M Tris stock solution.

Using stocks of 1 M Tris and 500 mM EDTA, describe how to prepare 50 mL of a 100 mM Tris, 5 mM EDTA working solution

Explanation / Answer

Ans 1 .

8% w/w means 8 g of compound in 100 g of mixture

Since here the mixture to be prepared is 500 g

the amount of gypsum required will be 8 x 5 = 40 grams

So 8% gypsum in sand mixture will have 500 - 40 = 460 grams of sand in it.

8% gypsum sand mixture = (40 grams of gypsum / 500 grams of mixture) x 100

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