Resources previous | 28 of 31 |next reagent, neither is limiting and both can be

Question

Resources previous | 28 of 31 |next reagent, neither is limiting and both can be used to calculate the theoretical yield Exercise 7.50 Enhanced with Feedback For the reaction Part B Mn (s) + O2 (g) MnO2 (s) mol Mn and9 mol 02 Express your answer using one significant figure compute the theoretical yield of product (in moles) for each of the following initial amounts of reactants 4 mol You may want to reference (-pages 299-306) Section 7.5 while completing this problem Submit ty Answers Give Up Correct Since the stoichiometry is 1 mol of MnOil form for every 1 mol of Mn and O2 that react, the reactant that is present in the least amount is limiting for this specific reaction, and that predicts the maximum amount of product that will form theoretically Part C 26.5 mol Mn and 42.8 mol 02 Express your answer using three significant figures. mol Submit tty Answers Give Up Continue

Explanation / Answer

C)

we have the Balanced chemical equation as:

Mn + O2 ---> MnO2

1 mol of Mn reacts with 1 mol of O2

for 26.5 mol of Mn, 26.5 mol of O2 is required

But we have 42.8 mol of O2

so, Mn is limiting reagent

we will use Mn in further calculation

From balanced chemical reaction, we see that

when 1 mol of Mn reacts, 1 mol of MnO2 is formed

mol of MnO2 formed = (1/1)* moles of Mn

= (1/1)*26.5

= 26.5 mol

Answer: 26.5 mol

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