Ethane burns in air to form carbon dioxide and water. The equation is 2C2H6(g) +

Question

Ethane burns in air to form carbon dioxide and water. The equation is

2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g)

Part A

In the above equation, how many liters of oxygen (O2) are required to burn 8.0  L of ethane (C2H6) gas? Assume that both gases are measured at the same temperature and pressure.

Part B

2C2H6(g)+7O2(g)4CO2(g)+6H2O(g)

In the equation above, what volume of ethane (C2H6) in liters is required to form 24  L of carbon dioxide (CO2)?

Part C

2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g)

In the equation, if 14 L of ethane (C2H6) and 14 L of oxygen (O2) combined and burned to completion, which gas will be leftover after the reaction, and what is the volume of that gas remaining?

Enter the name of the gas followed by its volume in liters to the nearest whole number, separated by a comma.

Explanation / Answer

2C2H6(g) + 7O2(g) 4CO2(g) + 6H2O(g)

A) according to balanced reaction

2 x 22.4 L ethane reacts with 7 x 22.4 L O2

8.0 L ethane reacts with 8.0 x 7 x 22.4 / 2 x 22.4 = 28.0 L

volume of O2 reacted = 28.0 L

B) 4 x 22.4 L CO2 require 2 x 22.4 L C2H6

24 L CO2 require 24 x 2 x22.4 / 4 x 22.4 = 12.0 L

volume of C2H6 reacted = 12.0 L

C) 2 x 22.4 L C2H6 reacts with 7 x 22.4 L O2

X L C2H6 reacts with 14 L O2

X = 14 x 2 x 22.4 / 7x22.4 = 4.0 L C2H6

exess C2H6 left = 14 - 4.0 = 10.0 L

exess C2H6 left = 10.0 L

C2H6 , 10.0 L

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