Nine Test Tube Mystery: 36 Metathesis Reactions. Please complete the following t

Question

Nine Test Tube Mystery: 36 Metathesis Reactions. Please complete the following table, following the guidelines that 1 a-e and 2 (especially to the descriptive words used in 2, e.g. cloudiness) describe. Use the following compounds: The purpose of this lab is to determine which one of the solutions listed below is found in each of the nine test tubes given to you by mixing them only. The nine possible solutions are: 0.1 M BaCl2 6 M NH 6 M NaOH 0.1 M CuSO 0.1 M Pb(NO)2 0.1 M AINO) 0.1 M Na CO, 6M HCI 3 M H,SO, 4 For Example, what would HCl + H2SO4 produce? What sort of physical state will it produce? Please do this for the rest of the compounds and reagents. You do not need to do a reaction with itself (e.g. HCl + HCl). Use 1a-e, and 2 as guidelines. Please only complete the chart below.

sheet. a. Note that you do not have to show each substance reacting with itself. b. In additign, you only have show the reaction between two substances one time. For example, once you have written the possible reaction between HCl and HSO, that appears on the first row of the pre-lab prediction grid, you do NOT have to also show the reaction between H,SO, and HCl that appears in the second row of the prediction grid Consult the solubility rules handout to help you predict if the products that form in these metathesis eactions will be solids or gases. c. d. Don't forget to consider the possibility of complex ion formation as mentioned in the background information. When you have finished, you will have written 36 possible reactions in your journal. Be sure they are balanced! e. 2. Once you know the expected products from each reaction, fill in the pre-lab prediction grid sheet to show what you expect to observe for each combination of reactants: cloudiness, bubbles, evolution of heat, or no reaction (NR). Even though you only had to write 36 reactions, you should fill in all of the combinations on the prediction grid. Be sure to attach this to your lab report.

Explanation / Answer

for HCl

HCl + H2SO4 ==== no reaction

HCl + NaOH ==== NaCl + H2O

HCl + NH3 === NH4Cl

2 HCl + CuSO4 ===== CuCl2 + H2SO4

3 HCl + Al(NO3)3 ====== Al Cl3 + 3HNO3

HCl + BaCl2 ==== no reaction will occur

HCl + Na2CO3 ===== 2NaCl + CO2 + H2O

HCl + Pb(NO3)2 ======= PbCl2 + 2 HNO3

for H2SO4

H2SO4 + 2NaOH = Na2SO4 +2 H2O

H2SO4 + 2NH3 ==== (NH4)2SO4 +

H2SO4 + Pb(NO3)2 ===== PbSO4 + 2HNO3

3H2SO4 + 2 Al(NO3)3 ===== Al2(SO4)3 + 6 HNO3

H2SO4 + BaCl2 ===== BaSO4 + 2HCl

H2SO4 + CuSO4 ==== no reaction

H2SO4 + Na2CO3 ===== H2CO3 + Na2SO4

for NaOH

NH3 + NaOH ===== no reaction

3 NaOH + Al(NO3)3 ==== Al(OH)3 + 3 NaNO3

2 NaOH + BaCl2 ====== Ba(OH)2 + 2NaCl

2 NaOH + CuSO4 ===== Cu(OH)2 + Na2SO4

NaOH + Na2CO3 ====== No reaction

2 NaOH + Pb(NO3)2 ===== Pb(OH)2 + 2 NaNO3

for NH3

3(NH3*H2O) + Al(NO3)3  ==== Al(OH)3 + 3NH4NO3

2(NH3*H2O) + BaCl2 ==== Ba(OH)2 + 2NH4Cl

NH3 + CuSO4 ==== [ Cu(NH3 )4] SO4

2(NH3*H2O)  + Pb(NO3)2 ==== Pb(OH)2 + 2NH4NO3

NH3 + Na2CO3 ==== no reaction

for Al(NO3)3

2 Al(NO3)3 + 3 BaCl2 ==== 3 Ba(NO3)2 + 2 AlCl3

2 Al(NO3)3 + 3 CuSO4 === 3Cu(NO3)2 + Al2 (SO4)3

2 Al(NO3)3 + 3 Na2CO3 ==== Al2(CO3)3 + 6 NaNO3

Al(NO3)3 + Pb(NO3)2 === no reaction

for BaCl2

BaCl2 + CuSO4 ==== CuCl2 + BaSO4

BaCl2 + Na2CO3 ==== BaCO3 + 2NaCl

BaCl2 + Pb(NO3)2 ==== PbCl2 + Ba(NO3)2

for CuSO4

CuSO4 +  Na2CO3 === CuCO3 + BaSO4

CuSO4 + Pb(NO3)2 ==== Cu(NO3)2 + PbSO4

for Pb(NO3)2

Pb(NO3)2 + Na2CO3 ==== 2 NaNO3 + PbCO3

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