Atomic Coatings Data and Results Table Trial 1 Trial 2 Length of galvanized iron

Question

Atomic Coatings Data and Results Table Trial 1 Trial 2 Length of galvanized iron (cm) Width of galvanized iron (em) Mass of galvanized iron, initial &) Mass of galvanized iron, final (g) Mass of zinc coating (g) Volume of zinc coating (em) Volume of zinc coating per side (cm2) Thickness of coating per side (cm) Number of layers of zinc atoms per side e. 5,011- Post-Lab Calculations (Show all work on a separate piece of paper. Enter the results of the caleulations in the Data and Results Table) 1. Subtract the final mass of galvanized iron from the initial mass of galvanized iron to calculate the mass of the zinc coating 2. The density of zinc is equal to 7.14 glem. Calculate the volume of zine metal corresponding to the mass of the zinc coat- 3. The zinc coating was present on both sides of the piece of galvanized iron. Divide the volume of the zinc coating by two to 4, (a) The formula for the volume (V) of a rectangular solid is V-L × W × H. Rearrange this formula to solve for the on the piece of galvanized iron. ing on the piece of galvanized iron. Hint: Rearrange the formula for density to solve for the volume of zinc. determine the volume of the zinc coating per side of the galvanized iron. height (H, thickness) of a rectangular solid if the volume (V), length (L), and width (W) of the solid are known. (b) Solve the above equation for the thickness of the zinc coating per side of the galvanized iron: Substitute the known values for the volume (per side) and the length and width of the galvanized iron into the formula. iron by the diameter of a single zinc atom to calculate the number of layers of atoms in the zine coating. Number of layers of zinc atoms = 5·The diameter of a single zinc atom is 2.7 × 10-8 cm. Divide the thickness of the zinc coating per side of the galvanized Thickness of zinc coating per side (em) Diameter of zine atom (cm)

Explanation / Answer

Atomic coating

From the data given in the table above,

1. mass of zinc coating = 3.21 - 3.09 = 0.12 g

2. density of zinc = 7.14 g/cm^3

density = mass/volume

so,

volume of zinc coating = 0.12 g/7.14 g/cm^3 = 0.017 cm^3

3. Volume of zinc coating per side = 0.017/2 = 0.0085 cm^3

4. (a) using,

volume = length x width x height

so,

height (thickness) of rectangular solid = 0.017cm^3/3.5cm x 3.0cm = 0.0016 cm

(b) thickness of zinc coating per side of galvanized iron = 0.0016/2 = 0.00081 cm

5. diameter of single zinc atom = 2.7 x 10^-8 cm

So,

Number of layers of zinc atom = thickness/diameter

feeding the value for thickness and diameter

number of layers of zinc coating = 0.00081 cm/2.7 x 10^-8 cm = 30,000 layers

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