What is the standard change im Gibbs energy for the reaction, as written, in the

Question

What is the standard change im Gibbs energy for the reaction, as written, in the forward direction? What is the equilibrium constant?

Substance(kJ/mol) M203 |-8.00 M(s) O2(g) Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M203(s) 2M(s) +802(g) What is the standard change in Gibbs energy for the reaction, as written, in the forward direction? Number k.J/ mol rxn What is the equilibrium constant of this reaction, as written, in the forward direction at 298 K? Number What is the equilibrium pressure of O2(g) over M(s) at 298 K? Number atm

Explanation / Answer

Ans dG = G(product) - G(reactant)

= 2G(M) + 3/2 G(O2) - G(M2O3)

= 0 + 0 - (-8)

dG = 8 KJ/mol

dG = -2.303 R T log Kp

8000 = - 2.303 * 8.314 * 298 log Kp

log Kp = -1.40

Kp = antilog (-1.4) = 0.039

Ans Kp = (PO2)^3/2 = 0.039

Po2 = 0.115 atm

P

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