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November 10, 2017 Name Lecture Assignment#7 (Chapter Nine) Extra Problemt1. The

ID: 561586 • Letter: N

Question

November 10, 2017 Name Lecture Assignment#7 (Chapter Nine) Extra Problemt1. The solubility of MgSO, is 35.1 g/100 g H20 at 20.0°c and 59.2 g/100 g H20 at 70.0°c a) Is a solution that is made by dissolving 100 g MgSO4 in 275 ml of water saturated or unsaturated at 20.0°C? at 70.0°C? How many grams of the 100 g of MgSO4 remains dissolved in 275mL H2O at 20.0°C? at 70.0°C? (assume density of 1.00g/ml) b) c) How many grams of the 100 g of MgSO4 dissolved in 275mL H20 precipitates out of solution (if any) at 20.0°C? at 70.0°C? (assume density of 1.00g/ml)

Explanation / Answer

a)

solubility given = 100g/275mL

density of water = 1g/mL

275 mL x 1g/mL = 275g

dissolving 100g in 275 g water = 100g/275g = 36.36g/100g

this is giving 36.36g solid dissolved in 100g water

but max. that can be dissolved is = 35.1g / 100g water ,hence the solution is saturated

solubility at 20 oC cannot be more than 35.1g/100g and hence the solution is saturated at 20 oC, but It is unsaturated at 70 oC as solubility = 59.2g/100g

as max. solubility at 70 oC is given as 59.2g per 100g water but we have only 36.36g /100g water solution and hence more MgSO4 can be dissolved till it reached 59.2g per 100g water

b)

we have 35.1g/100g as solubility

35.1g in 100g solvent

100g will need = 100/35.1 x 100 = 284.9 g water

but we have only 275 mL = 275 mL x 1g/mL = 275 g

and hence the soultion is saturated and dissolved MgSO4 is given by the solubility given

= 275g x 35.1g/100g = 96.525 g

at 70 oC 59.2g/100g as we have already seen that the solution is unsaturated at 70 oC and all 100g will be dissolved

c)

undissolved = 100g in sample - 95.525g in solution = 3.475g undissolved

at 70 oC no undissolved as solution is completely soluble that is 100g solid dissolved and undissolved =0

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