(A.) Phosgene is a deadly gas made up of carbon, oxygen and chlorine. Its densit
ID: 561740 • Letter: #
Question
(A.) Phosgene is a deadly gas made up of carbon, oxygen and chlorine. Its density at 1.05 atm and 25C. is 4.24 g/L. Show that the molecular formula of phossgene is COCl2 if it's compostion is 12.1 % carbon, 16.2% oxygen, and 71.7% chlorine by mass.
(B.) When exposed to UV light, phosgene, decomposes according to the reaction
COCl2(g)------>CO(g)+Cl2(g)
All the air removed from a 44.8 L flask. The flask is then filled the phosgene to a pressure of 1.0 atm at temperatue 0.C. The flask is selaed and exposed to UV light. What are the partial pressure of the CO and Cl2 after the decompostion of phosgene is complete?
Pls show step by step on how each one is solved thank you in advance :)
Explanation / Answer
A) C = 12.1/12 = 1.008
Cl = 71.7/35.5 = 2.02
O = 16.2 /16 = 1.0125
simplest ratio
C = 1.008/1.008 = 1
cl = 2.02/1.008 = 2
O = 1.0125/1.008 = 1
empirical formula = COCl2
empirical formula mass = 12+16+2*35.5 = 99 g/mol
mOlarmass of phosgene = DRT/
= 4.24*0.0821*298/1.05
= 98.8 g/mol
molecular formula = COCl2
B) No of mol of COCl2 filled (n) = PV/RT
= 1*44.8/(0.0821*273.15)
= 2 mol
from equation, 1 mol COCl2(g) = 1mol CO(g) = 1 mol Cl2(g)
partial pressure of CO = 2*0.0821*273.15/44.8 = 1 atm
partial pressure of Cl2 = 2*0.0821*273.15/44.8 = 1 atm
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