If cells are placed in a solution containing 150 moles/m3 of sodium chloride (Na

Question

If cells are placed in a solution containing 150 moles/m3 of sodium chloride (NaCl), there is no osmotic pressure difference across the cell membrane. (The cell membrane is much more permeable to water than to these ions.) a) Show that 150 moles/m, is equal to 0.150 moles/liter. b) What is the total concentration of ions in the solution, given that sodium chloride dissociates into Na+ and Cl-? (The total concentration of ions is also called the osmotic strength. If given in moles of ions/liter, this is called the osmolarity of the solution. The units are then sometimes called Osmoles/L or Osmoles/m'.) c) If cells were instead placed in pure water at room temperature, what would be the osmotic pressure difference from inside the cell to outside? d) If cells were instead placed in a solution containing a total concentration of ions equal to 310 moles/, what would happen to the cells?

Explanation / Answer

a)

150 mol / m3 --> 0.150 mol /L

1000 L = 1 m3

then

150 mol / m3 * 1 m3 / 1000 L = 150/1000 mol /L = 0.150 mol /L

b)

total concentration

[NaCl] = 0.150 M

[Na+] = [Cl-] = 0.150

[ions] = 0.15+0.150 = 0.30 M

c)

Posm = MR*T

Posm = 0.30*0.082*298

Posm = 7.3308 atm

d)

Concentration increases, therefore the solution will receive more moles form the higher solution, due to concentration gradient change

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