please help with these 3 questions akeC ors 2req Use the References to acress im
ID: 562461 • Letter: P
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please help with these 3 questions
akeC ors 2req Use the References to acress important values if needed fer this uestion. Consider the following reaction where Ke-1.29 10 at 600 K f prs 2req pts 2req A reaction mixture was found to coetam 0.109 moles of COCh(g) 473-10.2 moles of C0(g), and 4,07-10-Z moles of Cl2(g), in a 1.00 liter contaimer Is the reaction at equilabrium If not, what direction must it run in ceder to reach equilsberum? The reaction quotient, Qe equals The reaction A. must run in the forward directice to reach equilibeium B. must run in the reverse disection to reach equilsbe C. ii at equildbeiu Escite aqui para buscarExplanation / Answer
c = 1.29*10^-2
COCl2(g) --------> CO(g) +Cl2(g)
[COCl2] = 0.109 moles/1L = 0.109M
[CO] = 4.73*10^-2 moles/1L = 4.73*10^-2M
[Cl2] = 4.07*10^-2mole/1L = 4.07*10^-2M
Qc = [CO][Cl2]/[COCl2]
= 4.73*10^-2* 4.07*10^-2/0.109
= 1.76*10^-2
Qc>KC the equilibrium shift to reactant side
B. must run in the reverse direction to reach equilibrium.
2.KC = 55.6
H2(g) + I2(g) ---------> 2HI(g)
[H2] = 2.61*10^-2mole/1L = 2.61*10^-2 M
[I2] = 3.67*10^-2mole/1L = 3.67*10^-2M
[HI] = 0.272moles/1L = 0.272M
Qc = [HI]^2/[H2][I2]
= (0.272)^2/2.61*10^-2*3.67*10^-2
= 77.24
Qc>Kc The equilibrium shift to reactant side ( reverse)
B. must run in the reverse direction to reach equilibrium.
3. NH4I(s) -----------> NH3(g) + HI(g)
[NH3] = 1.16*10^-2mole/1L = 1.16*10^-2M
[HI] = = 8.37*10^-3mole/1L = 8.37*10^-3M
Qc = [NH3][HI]
= 1.16*10^-2 *8.37*10^-3
Qc = 9.7*10^-5
Kc = 7*10^-5
Qc>Kc The equilibrium shift to reactant side ( reverse)
B. must run in the reverse direction to reach equilibrium.
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