til Tomorrow at 8 AM CST is allowed, with a one time 10% penalty to submitted sc

Question

til Tomorrow at 8 AM CST is allowed, with a one time 10% penalty to submitted score. Activity Information Use the References to access important values if needed for this question. For the following reaction, 3.42 grams of water are mixed with excess zine oxide. Assume that the percent yield of zine hydroxide is 73.5% zine oxide(s)+ water(I)z zinc hydroxide(aq) What is the theoretical yield of zine hydroxide? grams What is the actual yield of zinc hydroxide? grams Submit Answer Use Percent Yield: This is group attempt 1 of 5 Back Autosaved at 317 PM 8

Explanation / Answer

molar mass of H2O 18 g/mol
number of mole of H2O = (given mass)/(molar mass)
= 3.42/18.0
= 0.19 mole

reaction taking place is
ZnO + H2O --> Zn(OH)2

according to reaction
1 mol of H2O give 1 mol of Zn(OH)2
0.19 mol of H2O give 0.19 mol of Zn(OH)2
number of theoretical mol of Zn(OH)2 = 0.19 mol

molar mass of Zn(OH)2 = 99.4 g/mol
mass of Zn(OH)2 = (number of theoretical mol of Zn(OH)2)*(number of theoretical mol of Zn(OH)2)
= 0.19*99.4
= 18.9 g

theoretical yield of Zn(OH)2 = 18.9 g

use,
actual yield of Zn(OH)2 = {(theoretical yield of Zn(OH)2)*(percentage yield)}/100
= (18.9*73.5)/100
= 13.9 g

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.