pietely: I mol Na × 1 mol C12 2 mol Na RT moles Na Na moles C12- liters ci 2 Exa
ID: 563289 • Letter: P
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pietely: I mol Na × 1 mol C12 2 mol Na RT moles Na Na moles C12- liters ci 2 Example 1114 shows how to use the ideal gas equation in a stoichiometric analysis. Worked Example 11.14 sadium peroxide (Na,O,) is used to remove carbon dioxide from (and add oxygen to) the air supply in reacting with cOinthe air to produce sodium carbonate (Na,CO) and O (in liters) of CO2 (at STPwill react with a kilogram of Na,O? What volume crategy Convert the given mass of Na,O, to moles, use the balanced equation to determine the coichiometrie amount of CO, and then use the ideal gas equation to convert moles of CO, to liters. Setup The molar mass of Na,O, is 77.98 g/mol (l kg 1000 g). (Treat the specified mass of Na,o, as an exact number.) I mol Na2o, = 12.82 mol Na,Or 2 mol CO2 CO2 12.82 mol do, 12.82 met NaO. × 2 2 2.mol.N (12.82 mol CO,(0.08206 L atm/K mol)Y273.15 K) = 287.4 LCO. l atm Think About It he answer seems like an enormous volume of CO, If you check the cancellation of units carefully in ideal equation problems, however, with practice you will develop a sense of whether such a calculated olume is reasonable. Practice Problem A TTEMPT What volume (in liters) of CO, can be consumed at STP by 525 g rc Problem BUILD What mass (in grams) of Na,0, is necessary to consume 1.00L co Problen CoNCEPTUALIZE The decomposition reactions of two solid compounds here.Explanation / Answer
Molar mass of Na2O2,
MM = 2*MM(Na) + 2*MM(O)
= 2*22.99 + 2*16.0
= 77.98 g/mol
mass of Na2O2 = 1000 g
mol of Na2O2 = (mass)/(molar mass)
= 1000/77.98
= 12.82 mol
According to balanced equation
mol of CO2 reacted = moles of Na2O2
= 12.82 mol
1 mol of gas at STP is 22.4 L
So,
volume = number of mol * 22.4 L
= 12.82 * 22.4 L
= 287 L
Answer: 287 L
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