Chapter 16 Lecture Chapter 15 Lecture sidesp, . CHE ×°) Course: 2016,SP Chemical

Question

Chapter 16 Lecture Chapter 15 Lecture sidesp, . CHE ×°) Course: 2016,SP Chemical [ rsity www.saplingleaming.com/ibiscms/modibis/viewphp?id.4961201 lect then , and drag to the Favorites Bar folder. Or import from another browser. Import favorites arning Gradebook 2/12/2018 08:00 AM 0 351100 Score Qvestion 5 of 20 Sapling Learning Express the concentration of a 0.0520 M aqueous solution of fluoride, F, in mass percentage and in parts per milion. Assume the density of the solution is 1.00 g/mL Number Number Ppm OPrevas Give Up & View Souton 0Check Answer e Next ijfxit search

Explanation / Answer

Let's assume that you have 1 L of solution.

Molarity = Moles / Liter

So, moles of F- = Molarity of F- x Liters of F-
= (0.0520 M) x (1 L)
= 0.0520 moles F-

0.0520 moles F- x (19.0 g F- / 1 mole F-) = 0.988 g of F- in 1 L of solution.

Now,

1 L solution x (1000 mL / 1 L) x (1.00 g / mL) = 1000 g solution.

So, mass % F- = (g F- / g solution) x 100
  = (0.988 / 1000) x 100
  = 0.0988 %

part par million = mg/L

parts per million F- = (mg of F-) / L
  = (988 mg) / (1 L)
  = 988 mg/L
= 988 ppm

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