Sprint LTE 8:01 PM webassign.net Supporting Mateials Period. Table Constares and

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Sprint LTE 8:01 PM webassign.net Supporting Mateials Period. Table Constares and On a humid day in New Orleans, the temperature is 20.7°C, and the partial pressure of water vapor in the air is 32.4 torr. The 9000-ton air-conditioning system in the Louisiana Superdome maintains an inside air temperature of 20.7°C also, but a partial pressure of water vapor of 10.0 torr. The volume of air in the dome is 2.4 x 106 m3, and the total pressure is 1.0 atm both inside and outside the dome. (a) What mass of water (in metric tons) must be removed every time the inside air is completely replaced with outside air? (Hint: How many moles of gas are in the dome? How many moles of water vapor? How many moles of dry air? How many moles of outside air must be added to the air in the dome to simulate the composition of outside air?) Your response differs from the correct answer by more than 10%. Double check your calculations. metric tons (b) Find the heat released when this mass of water condenses. k) Supporting Materials Periadic Table Home My Assignments Extension Reques

Explanation / Answer

Use the ideal gas equation to calculate the moles of water

so you have pressure for water 32.4 torr, change this to atm, divide the value by 760

32.4 / 760 = 0.04263 atm

volume is 2.4 x 106 m3, 1 m3 has 1000 liters so

the volume is 2.4 x 109 liters

Temperature is 20.7 C

change it to kelvin with 20.7 + 273.15 = 293.85 Kelvin

apply the ideal gas equation

PV = n RT

n = 0.04263 atm * 2.4 x 109 liters / (0.082 * 293.85) = 4246226.068

remember that 1 mole of water has a mass of 18 g/gmol somoles

4246226.068 moles * 18 = 76,432,069.23 grams

Repeat this calculations with

Temperature = 20.7 C = 293.85 Kelvin

and Pressure = 10 torrs

1 atm = 760 torr

10 / 760 = 0.01315 atm

Volume = 2.4 x 109 liters

apply the ideal gas equation you will get a value for moles = 1310563.601 moles of water

multiply by 18 to get =  1310563.601 * 18 = 23,590,144.82 grams

get the difference of masses

76,432,069.23 - 23,590,144.82 = 52841924.41 grams

change this to metric tons

1 ton is 1 000 000 grams so

52.84 tons of air must be removed

b) we need to turn the last value to moles

divide the value by 18 to get 2,935,662.47 moles of water or 2.935 x 106 moles of water

heat of condensation of water is -40.7 KJ / mol so

2.935 x 106 * - 40.7 KJ / mol = -1.19 x 108 KJ

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