You decide to collect the water vapor created by the reaction in a 2.0 L balloon

Question

You decide to collect the water vapor created by the reaction in a 2.0 L balloon. Assuming 100% yield of the combustion, what will be the pressure of the water vapor in the balloon at 25 °C? (4 pts) b. Sulfur hexafluoride (SFo) is an extremely dense gas commonly used in insulated double-pane windows. Predict the density of SFs at 1 atm of pressure and 273.15 K. Look up the actual density of SFs online. Does your prediction match the actual value? If it does not, propose one explanation why they might differ. (4 pts) 2. Predicted Density Actual Density

Explanation / Answer

The first question part b, is incomplete the reaction is missing

For the second part

Rearrange the ideal gas equation

molar mass of SF6 is 146.06 g/gmol

PV = n RT

n = moles = mass / molar mass

P is pressure, R is gas constant

T is temperature so

PV = mass / molar mass * RT

P * molar mass = mass / V RT

density is mass / volume so

P*molar mass = density RT

so

Density = P*molar mass / (RT) = 1 * 146.06 / (0.082*273.15) = 6.5 g/L

i am getting a value of 6.17 g/L, this value is at 25C

the difference might be because at 0 C (273.15) the molecules do not have too much energy

at 25 C the molecules increase their energy and expand, so the gas occupies more volume for the same mass

density = mass / volume

if mass is the same and volume increases then density decreases

*if this answer is helpful dont forget to rate it =)

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