Cu(NO3)2 NaCl NP Na2S X- blue product NaOH X - blue product Na2CO3 X- blue produ
ID: 563972 • Letter: C
Question
Cu(NO3)2
NaCl NP
Na2S X- blue product
NaOH X - blue product
Na2CO3 X- blue product
X = precipitate form ; NP = no precipitate form
Did the student conduct the experiment correctly?
A. No, the student mistakenly added Mg(NO3)2 solution instead of the Cu(NO3)2 solution.
B. No, the student mistakenly added Fe(NO3)3 solution instead of the Cu(NO3)2 solution.
C. No, the student mistakenly added AgNO3 solution instead of the Cu(NO3)2 solution.
D. No, the student mistakenly added NaOH solution instead of the Cu(NO3)2 solution.
E. Yes, the student performed the experiment correctly.
Explanation / Answer
Qualitative analysis
No precipitate was formed in the given experiment, therefore,
D. No, the student mistakenly added NaOH solution instead of the Cu(NO3)2 solution.
Explanation : Cu(NO3)2 forms insoluble precipitate with NaOH, Na2S and Na2CO3, which is not seen here, therefore, the student did not add Cu(NO3)2. Mg(NO3)2 is also known to form insoluble precipitate NaOH. Fe(NO3)3 also forms precipitate with all three NaOH, Na2S and Na2CO3 like Cu(NO3)2. AgNO3 forms AgCl with NaCl. Therefore, none of the salts Cu(NO3)2, Fe(NO3)2 or AgNO3 is present in solution.
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