I was working on my lab for chemistry and was only able to get this far. Im not

Question

I was working on my lab for chemistry and was only able to get this far. Im not sure how to do part 2b and 2c. Included my observed data. Thank you

Data Tables Data Table 1. Find the Volume of One Drop of Solution. Mass of empty beaker (a) Mass of beaker plus 5 drops of water (b) Mass of first 5 drops of water (b) -(a) Average mass of 1 drop of water Mass of beaker plus 10 drops of water (c) Mass of second 5 drops of water (c) -(b) Average mass of 1 drop of water Mass of beaker plus 15 drops of water (d) Mass of third 5 drops of water (d) - (c) Average mass of 1 drop of water Trial 1 Trial 2 Trial 3 Average mass of 1 drop of water (Trials 1-3) Data Table 2. Determine the Reaction Rate and Calculate the Rate Law. ,-E, Time, seconds Experiment No. Trial 3 Average Temp. C Trial 1 Trial 2 do do

Explanation / Answer

2b.

To calculate this , you have to follow this

let intial concentration is C1 , Initial volume Is = V1

Concentration after dilution = C2 , volume after dilution = V2 = (V1+ volume added)

now

C1V1 = C2V2

then , C1 = C2V2/V1

2d.

To calculate the rate

from the equation , K[I-]x[BrO3-]y[H+]z (1)

calculate the rate of reaction by changing one reactant and keeping the other reactants constant.

You can follow the given procedure

let Rate = 2 *10-3 , when concentration of I- = P , [BrO3-] = Q , and [H+] = R

if concentration of [I-] changes to 2p, let rate is 4*10-3 ( concentration of others are constant)

and if concentration of [BrO3-] changes to 2Q then the rate is 8*10-3 ( concentration of others are constant)

and if  concentration of [H+] changes to 2R then  the rate is 2*10-3

now you can put the data in the equation 1

2*10-3 = K. Px. Qy. Rz (i)

4*10-3 = K .(2P)xQy. Rz (ii)

8*10-3 = K. Px. (2Q)y. Rz (iii)

2*10-3 = K. Px. Qy. (2R)z  (iv)

now divide (i) and (ii)

2/4 = Px/(2P)x

or, 1/2 = (1/2)x ; or, x = 1

again divide (i) by (iii)

2/8 = Qy/ (2Q)y

or, 1/4 = (1/2)y ; or, y = 2

again divide (i) by (iv)

1/1 = Rz/ (2R)z

or, 1 = (1/2)z

or, Z = 0

hence, order of the reaction is = 1+2+0 = 3

,By following the above process you can calculate the order of the reaction.

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