Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

need help with the calculations for this. density of a liquid. tia Report Sheet

ID: 564327 • Letter: N

Question

need help with the calculations for this. density of a liquid. tia

Report Sheet Name Date Section Vessel Mass of vessel with water Mass of empty vessel Mass of water Volume of water from vessel mark (expenmental value Volume of water from mass of water and exact density (Accepted or "true value) r, vol. flask, eteTrial Trial 2 Trial 3 73 Seg 13.5 88 | 3D mL 120 m 130mm Absolute error (experimental value - accepted value) absolute error true value x100% Average % error Using the averages from the data collected by the class, fill in the table below Absolute Error of beaker % Error of beaker Absolute Error of graduated cylinder % Error of graduated cylinder Absolute Error of volumetric flasik % Error of volumetric flask From the above analysis, which glassware device would provide the most accurate and precise measurements? What is there about the shape of that glassware that would lead to this result? Explain.

Explanation / Answer

Density of a liquid is given as the mass of the liquid contained in a given volume of the liquid. Mathematically it is given as Density = Mass/Volume.

From the given data, the mass of water is the difference between the mass of beaker + water and the mass of empty beaker which is given as: mass of water = 78.576 - 50.220 = 28.356g in Trial 1; 28.36g in Trial 2 and 28.37g in Trial 3.

The exact density of water determined experimentally is 0.99823g/mL.

Thus, 30mL of water should weigh 0.99823*30 = 29.9469g.

This gives the absolute error for Trial 1 to be 1.5909g, 1.5869g in Trial 2 and 1.5769g in Trial 3.

So now, the percentage errors for the first, second and third trials are 5.3124%, 5.299% and 5.2656% respectively.

Finally the average error % is calculated as (5.3124 + 5.299 + 5.2656)/3 = 5.2923%.