x Clutch UTD Prof Diek-EqExamReview.pdf UTD GENERAL CHEMISTRY II-PROF. DIECKMANN

Question

x Clutch UTD Prof Diek-EqExamReview.pdf UTD GENERAL CHEMISTRY II-PROF. DIECKMANN UTD CHEM 1312 DIECKMANN EXAM 2 REVIEW PRACTICE: The equilibrium constant for the reaction: Ag2SOds) 2Ag. (aq) + SO42-(aq) is Kc 1.8x10-10 If the So,2 concentration is 1.2x10-6 M, what is the Agt concentration? a) 0.221 b) 1.50x10-4 c) 2.25x10-8 d) 1.22x10-2 e) 8.66x10-6 PRACTICE: For a chemical reaction: Cl 2 (g) + (g) 2 CIO (g) has a KP-0.155, and the initial 0.55 atm Cl2 0.55 atm d0.45 atm CIO Solve for the final concentration of Cl2 in atm A. 0.098 B. 0.12 C. 0.42 D. 0.65 E. 0.67 * This review was not prepared by your protfessor or school and is neither approved nor endorsed by your college or university

Explanation / Answer

1) Kc = [Ag+] [SO4^2-]

1.8 x 10^-10 = [Ag+] (1.2 x 10^-6)

[Ag+] = 1.5 x 10^- 4 M , hence option B

2) at equilibrium pCl2 = 0.55+ X , pO2 = 0.55+ X , pClO = 0.45-2X

( which means 2X parts of ClO decomposed to form X atm Cl2 and X atm of O2 )

Kp = ( pClO)^2 / ( pCl2) ( pO2)

0.155 = (0.45-2X)^2 / ( 0.55+X) (0.55+X)

0.155 = [( 0.45-2X) / ( 0.55+X) ] ^2

0.3937 = (0.45-2X) / ( 0.55+X)

0.3937 (0.55+X) = 0.45-2X

0.2165 + 0.3937X = 0.45-2X

X = 0.09755

pCl2 = 0.55+0.09755 = 0.65 atm

Hence option D

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