25.00 ML of heavy water 2. 25.00 mL ofheavy water (D,0 where D is a hydrogen wit

Question

25.00 ML of heavy water 2. 25.00 mL ofheavy water (D,0 where D is a hydrogen with a neutron in its nucleus)at 20'C was pipetted into a 37.234 g beaker. The final mass of the beaker was 64.859 g a What is the density of heavy water at 20 C? b. The density of normal water (the hydrogens do not have neutrons) at 20'C is 0.9982 g/mL Calculate the density you would expect for heavy water by assuming that deuerium (H or D) is the same size as normal hydrogen ('H) when it is part of the water Based on your answer to (b), was the assumption in (b) justified? Explain your answer. c. gg.com/#books/9781 285965925/cfi/72V4/4@0.00:0.00

Explanation / Answer

a)

Density = mass / volume

change in mass = (64.859-37.234) = 27.625 g

D = 27.625 / 25.0

D = 1.105 g/mL

b)

If we assume:

V = 1 mL of sample;

mass in 1 mL:

1.105 g/mL

1.105 g of deuterium

Then, we will expect

D = 1.105 g/mL for deuterium

vs.

D = 0.9982 g/mL for water

This assumption is not likely to be correct

c)

Not likely, we can't simply assume sizes to be the same, since they will reppeal electrons form the nucleus differently.

Also, the amount of mass per atom is different

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