. Effect of Concentration on Degree of Ionization Record the pH, [H30*], and [OH
ID: 567778 • Letter: #
Question
. Effect of Concentration on Degree of Ionization Record the pH, [H30*], and [OH-1 of each solution that you investigated. 0.010 M 0.10 M 1.28 5.25 xl 1.0 M 2.02 pH (H30+] OH- HC2H302 pH (H30+] OH- HCI 25 3.9%x10 ' 10-13 1.05 x 10-1 3,14 2.51 00309 2.92 .o012 3.33410"12 IL 3.24oL 1.59%10 27 NH3(aq) pH [H30*1 OH-] 11.9q 1.025+lo· 009775 2.09%) S, 37.10 00479 Using your data, calculate the value of Ka or Ko and the degree of ionization, a, for each of the soluti investigated. 1.0 M 0.10 M 0.010 M HCI Ka Sample CalculationsExplanation / Answer
For the given solutions,
with 1.0 solution
HCl
Ka = [H3O+]^2/[HCl] = 0.251^2/1 = 0.063
alpha = (0.063 x 100)/1 = 6.30%
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HC2H3O2
Ka = (0.00309)^2/1 = 9.55 x 10^-6
alpha = 0.00309 x 100/1 = 0.309%
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NH3
Kb = [OH-]^2/[NH3] = (0.009775)^2/1.0 = 9.55 x 10^-5 M
alpha = 0.009775 x 100/1.0 = 0.98%
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with 0.1 solution
HCl
Ka = [H3O+]^2/[HCl] = (0.0525)^2/0.1 = 0.027
alpha = (0.0525 x 100)/0.1 = 52.5%
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HC2H3O2
Ka = (0.000724)^2/0.1 = 5.24 x 10^-6
alpha = 0.000724 x 100/0.1 = 0.72%
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NH3
Kb = [OH-]^2/[NH3] = (0.00479)^2/0.1 = 2.29 x 10^-4 M
alpha = 0.00479 x 100/0.1 = 4.79%
similarly for the 0.01 M solution values may be calculated.
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