Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

CONDUCTANCE OF SOLUTIONS Data/Calculations Sheet Date Section Name A. Write the

ID: 568500 • Letter: C

Question

CONDUCTANCE OF SOLUTIONS Data/Calculations Sheet Date Section Name A. Write the molecular form, the total ionic form, and the net ionic form of the chemical equations for the following chemical reactions. Calculate the theoretical volume of 1.0 M titrant necessary to titrate 50.0 ml of 0.10 M solution to the equivalence point for each of these three titrations. 1. Hydrochloric acid titrated by sodium hydroxide. 2. Acetic acid titrated by sodium hydroxide. 3. Barium chloride titrated by sodium sulfate Conductance of Solution

Explanation / Answer

1.

Molecular equation,

HCl (aq.) + NaOH (aq.) --------------> NaCl (aq.) + H2O (l)

Complete ionic equation:

H+ (aq.) + Cl- (aq.) + Na+ (aq.) + OH- (aq.) ---------> Na+ (aq.) + Cl- (aq.) + H2O (l)

Net ionic equation:

H+ (aq.) + OH- (aq.) ------------> H2O (l)

M1V1 / n1 = M2V2 / n2

0.1 * 50 / 1 = 1.0 * V2 / 1

V2 = 5 mL

2.

Molecular equation:

CH3COOH (aq.) + NaOH (aq.) ------------> CH3COONa (aq.) + H2O (l)

Complete ionic equation:

CH3COOH (aq.) + Na+ (aq.) + OH- (aq.) -----> CH3COO- (aq.) + Na+ (aq.) + H2O (l)

Net ionic equation:

CH3COOH (aq.) + OH- (aq.) -------> CH3COO- (aq.) + H2O (l)

M1V1 / n1 = M2V2 / n2

0.1 * 50 / 1 = 1.0 * V2 / 1

V2 = 5 mL

3.

Molecular equation:

BaCl2 (aq.) + Na2SO4 (aq.) ----------> BaSO4 (s) + 2 NaCl (aq.)

Complete ionic equation:

Ba2+ (aq.) + 2 Cl- (aq.) + 2 Na+ (aq.) + SO42- (aq.) ------> BaSO4 (s) + 2 Na+ (aq.) + 2 Cl- (aq.)

Net ionic equation:

Ba2+ (aq.) + SO42- (aq.) ----------> BaSO4 (s)

M1V1 / n1 = M2V2 / n2

0.1 * 50 / 1 = 1.0 * V2 / 1

V2 = 5 mL

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote