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page= 11 Student Resources Service Center Student Email Course ResourcesCourse EvaluationsJynneen Strong 12 Consider the unbalanced chemical equation: NH3+ 02 NO + H0 It requires 55.4 g of NH3 to completely react with 156 g of O2 swered Select one: t of True question False ous page enter Student Email | Library Resources | Book Store I Policies & Procedures | Student Services | Central Online I IP. Videos on Demand | Course Evaluations LCentral COMMUNITY COLLEGE You are logged in as Jynneen Strong (Log out) 18/SP CHEM-1050-DHWD1Explanation / Answer
The balanced equation is:
4 NH3 + 5 O2 —> 4 NO + 6 H2O
Lets say we have 156 g of O2
we will calculate the mass of NH3 required to react with O2
Molar mass of O2 = 32 g/mol
mass of O2 = 156 g
mol of O2 = (mass)/(molar mass)
= 156/32
= 4.875 mol
Balanced chemical equation is:
4 NH3 + 5 O2 —> 4 NO + 6 H2O
According to balanced equation
mol of NH3 formed = (4/5)* moles of O2
= (4/5)*4.875
= 3.9 mol
Molar mass of NH3,
MM = 1*MM(N) + 3*MM(H)
= 1*14.01 + 3*1.008
= 17.034 g/mol
mass of NH3 = number of mol * molar mass
= 3.9*17.034
= 66.4 g
So, 66.4 g of NH3 is required
Answer: False
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