Suppose you wanted to produce an aqueous solution of pH = 8.80 by dissolving one

Question

Suppose you wanted to produce an aqueous solution of pH = 8.80 by dissolving one of the following salts in water: NH4Cl, KHSO4, KNO2, NaNO3

Part B: At what molarity?

Homework: Chemical Equilibria (Chapters 15 & 16) Question 10 10 of 10 Suppose you wanted to produce an aqueous solution of pH-8.80 by dissolving one of the following salts in water: NH,Cl, KHSO4, KNO2 NaNO3 Part A Which salt would you use? NH4CI KHSO4 NaNO3 ious Ans Correct Part B At what molarity? Express your answer using two significant figures. molarity® 16.31. 10-6 Submit ious Ans Request Answen X Incorrect; Try Again; 3 attempts remaining

Explanation / Answer

PH= 8.80

POH + PH= 14

POH= 14-PH= 14 - 8.80= 5.2

POH= 5.2

-log[OH-]= 5.2

[OH-]= 10^-5.2

[OH-] = 6.3 x 10^-6M

KNO2 ------------- K+ NO2-

NO2- + H2O ------------- HNO2 + OH-

for HNO2 , ka= 4.5 x10^-4

Ka xKb = Kw

Kb= Kw/Ka = 1.0x10^-14/4,5x10^-4 = 2.22x10^-11

Kb= 2.22x10^-11

[OH-] = square root of KbxC

squaring on both sides

[OH-]^2 = Kb x C

C= [OH-]^2/Kb = ( 6.3x10^-6)^2/2.22x10^-11 = 17.87 x10^-1

C= 1.787M

Concentration = 1.787M= 1.79M

Related Questions

Navigate

• Browse (All)
• Browse S
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.