2/23/2018 11:55 PM Calculator -d Periodic Table Question 1 of 9 Sapling Learning

Question

2/23/2018 11:55 PM Calculator -d Periodic Table Question 1 of 9 Sapling Learning this question was written by Gen Chem Lab Coordinator at Western Washington University (V Explain why the conductivity of 0.122 M NaBr(aq) is about twice that of 0.061 M NaBr(aq). The nature of the ions in solution for 0.122 M NaBr are different than those in the 0.061 M NaBr and the ions in the 0.122 M NaBr carry the charge better O More ions flow past the conductivity probe in a given amount of time in 0.122 M The 0.122 M NaBr consists of Na2 and Br2 ions in solution whereas the 0.061 M NaBr only has Na" and Br ions in solution. There is a higher concentration of free ions in a 0.122 M NaBr than there is in a 0.061 M NaBr Since the 0.122 M NaBr is twice as concentrated as 0.061 M NaBr, each ion is allowed to carry twice as much electrical charge in solution. 0 Previous 0 Next Save And Exit

Explanation / Answer

NaBr is strong electrolyte.

so NaBR is completely ionized in aqueous solution to form Br- and Na+ ions.

NaBr ................> Na+ + Br-

As we know, ions are responsible for conduction of solution. because ions carry electricity.

0.122 M NaBr solution contians 0.122 M Na+ and 0.122 Br- ions.

0.061 M NaBr solution contains 0.061 M Na+ and 0.061 M Br-.

so concentration of ions in 0.122 M NaBr solution is twice of 0.061 M NaBr solution.

Hence LAST OPTION (fifth option) is the answer.

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