ment/take Activity dolocator assignment-take&ctakeAssignmentSess; ssignment-take
ID: 570229 • Letter: M
Question
ment/take Activity dolocator assignment-take&ctakeAssignmentSess; ssignment-take A student is asked to standandize a solution of potassium hydroxikle He weighs out 1.01 g potassium bhydlrogen phthalate (KHCH,0s, treat this as a monoprotic acid). It requaires 1S.9 ml. of potassium hydroxide to reach the endpoint A. What is the molarity of the potassiums hydroxide solution? This potassium hydroxide solution is then used to titrate an unknown solution of perchlork acid R. 11 22.8 ml of the potassiumm hydroside solution is roqaired so neutralize 29.3 ml of perchloric ackd, what is the molarity of the perchlorkc acid solutice? Submit Answer more group atempts remaining 2/24/2018Explanation / Answer
Molar mass of Potassium Hydrogen pthalate (C8H5KO4) = 8 * 12 + 5 * 1 + 39 + 4 * 16 = 204 gm/mol
Number of moles = Mass/molar mass = 1.01/204 = 0.00495098039 moles
Number of moles of Potassium Hydroxide solution = Number of moles of monoprotic acid
Molarity * Volume of solution (in L) = 0.00495098039
15.9/1000 * Molarity = 0.00495098039
Molarity = 0.31138M
b)
Now the number of moles of Potassium Hydroxide solution must be equal to perchloric acid
Molarity(M)(KOH) * Volume of KOH = Molarity M(Per chloric acid) * Volume of perchloric acid
0.31138 * 22.0 = Molarity of Perchloric acid * 29.3
Molarity of Perchloric acid = 0.2338M
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